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ignore corrupt files cache, fixes #2939
ignore the files cache when corrupt and emit a warning message so the users notices that there is a problem.
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1 changed files with 10 additions and 4 deletions
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@ -208,10 +208,16 @@ def _read_files(self):
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if not data:
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break
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u.feed(data)
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for path_hash, item in u:
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item[0] += 1
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# in the end, this takes about 240 Bytes per file
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self.files[path_hash] = msgpack.packb(item)
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try:
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for path_hash, item in u:
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item[0] += 1
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# in the end, this takes about 240 Bytes per file
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self.files[path_hash] = msgpack.packb(item)
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except (TypeError, ValueError) as exc:
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logger.warning('The files cache seems corrupt, ignoring it. '
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'Expect lower performance. [%s]' % str(exc))
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self.files = {}
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return
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def begin_txn(self):
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# Initialize transaction snapshot
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