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FIX:(#1796) When renaming issues, if issue number was not a non-padded number and annuals were enabled would not return valid results, FIX: (#1796) When searching against CV with multiple common terms, would improperly remove characters without adjusting for previous changes

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evilhero 2017-12-13 10:40:43 -05:00
parent 6f133be1ef
commit b29a732f28
2 changed files with 13 additions and 13 deletions
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5
mylar/helpers.py
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@ -291,9 +291,8 @@ def rename_param(comicid, comicname, issue, ofilename, comicyear=None, issueid=N
#this has to be adjusted to be able to include story arc issues that span multiple arcs
chkissue = myDB.selectone("SELECT * from readinglist WHERE ComicID=? AND Issue_Number=?", [comicid, issue]).fetchone()
else:
if all([annualize is None, not mylar.CONFIG.ANNUALS_ON]):
chkissue = myDB.selectone("SELECT * from issues WHERE ComicID=? AND Issue_Number=?", [comicid, issue]).fetchone()
else:
if all([chkissue is None, annualize is None, not mylar.CONFIG.ANNUALS_ON]):
chkissue = myDB.selectone("SELECT * from annuals WHERE ComicID=? AND Issue_Number=?", [comicid, issue]).fetchone()
if chkissue is None:
@ -302,7 +301,7 @@ def rename_param(comicid, comicname, issue, ofilename, comicyear=None, issueid=N
chkissue = myDB.selectone("SELECT * from readinglist WHERE ComicID=? AND Int_IssueNumber=?", [comicid, issuedigits(issue)]).fetchone()
else:
chkissue = myDB.selectone("SELECT * from issues WHERE ComicID=? AND Int_IssueNumber=?", [comicid, issuedigits(issue)]).fetchone()
if all([annualize == 'yes', mylar.CONFIG.ANNUALS_ON]):
if all([chkissue is None, annualize == 'yes', mylar.CONFIG.ANNUALS_ON]):
chkissue = myDB.selectone("SELECT * from annuals WHERE ComicID=? AND Int_IssueNumber=?", [comicid, issuedigits(issue)]).fetchone()
if chkissue is None:

5
mylar/mb.py
View file

@ -87,15 +87,16 @@ def findComic(name, mode, issue, limityear=None, type=None):
commons = ['and', 'the', '&', '-']
for x in commons:
if x in name.lower():
cnt = 0
for m in re.finditer(x, name.lower()):
cnt +=1
tehstart = m.start()
tehend = m.end()
if any([x == 'the', x == 'and']):
if not all([tehstart == 0, name[tehend] == ' ']) or not all([tehstart != 0, name[tehstart-1] == ' ', name[tehend] == ' ']):
continue
else:
name = name[tehstart:tehend].replace(x, ' ').strip() + name[tehend+1:]
name = name.replace(x, ' ', cnt)
pattern = re.compile(ur'\w+', re.UNICODE)
name = pattern.findall(name)